121x^2+1=22x

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Solution for 121x^2+1=22x equation: 



121x^2+1=22x

We move all terms to the left:

121x^2+1-(22x)=0

a = 121; b = -22; c = +1;
Δ = b2-4ac
Δ = -222-4·121·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{22}{242}=1/11$

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